I = I0 eαd [Considering only Primary ionization]
I = I0 eαd / [1 – γ (eαd – 1)] [Considering both Primary and secondary ionization]
Let n0 be the number of electrons released from cathode due to UV radiations.
n+
nd – number of electrons reaching anode.
γ = Townsends secondary ionization coefficient i.e. number of electrons released from cathode per incident positive ion, photon or metastable.
We have equation from Townsends primary ionizaton as,
nd = n0 eαd
The equation changes to
nd = (n0 + n+) eαd
Here n0 + n+ – are the number of electrons at the cathode,
n+ = (additional electron) γ
n+ = [ nd – (n0 +
n+)]y
Note : Solve bracket, take n+ on L.H.S. remaining part on R.H.S., put n+ value in Equation (1) and (2), simplify and get the value for nd’ nd / time is current equation.
n+ = nd . y – n0 .γ – n+
.γ
n+ + n+ .γ = nd . y – n0
.γ
n+ (1 + γ) = nd . y – n0 .γ
n+ = y (nd – n0) / (1 + γ)
Put value of n+ in Eqn (2)
nd = [n0 + γ (nd – n0) / (1 + γ)] eαd
[n0 + n0.y + nd.y-
n0.y / (1 + γ)] eαd
nd = [n0 + nd.γ / (1 + γ)] eαd
nd (1 + γ) = n0 + nd γ
nd + nd.γ = n0. eαd + nd.γ.
eαd
nd + nd.y – nd.γ.
eαd = n0. eαd
nd (1 + y – γ. eαd) = n0. eαd
nd = n0. eαd / [1 + γ (1 – eαd)]
Divided by time,
nd / t = = n0. eαd / [1 + γ (1 – eαd)] /t
I = I0 . eαd/ 1 – y (eαd – 1)
This is Townsend’s current grown equation due to (α) primary and secondary (γ) ionization.